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CommonSubstring.java
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76 lines (68 loc) · 2.22 KB
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/**
* Common Substring - Three String Values
* The program must accept three string values S1, S2 and S3 as the input.
* The program must print the longest common substring in S1, S2 and S3.
* If there are two or more longest common substring values, the program must print the first occurring longest common substring.
* If there is no such longest common substring, the program must print -1 as the output.
*
* Boundary Condition(s):
* 2 <= Length of S1, S2, S3 <= 100
*
* Input Format:
* The first line contains S1, S2 and S3 separated by a space.
*
* Output Format:
* The first line contains the longest common substring in S1, S2 and S3 or -1.
*
* Example Input/Output 1:
* Input:
* Abcdefghxyz xyz Abcxyz
* Output:
* xyz
* Explanation:
* The longest common substring in Abcdefghxyz, xyz and Abcxyz is xyz.
* So xyz is printed as the output.
*
* Example Input/Output 2:
* Input:
* Pqrstuv Ab@cdefgh ijklmn@
* Output:
* -1
*
* Max Execution Time Limit: 500 millisecs
* */
import java.util.*;
class LongestCommonSubstring {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String S1 = sc.next();
String S2 = sc.next();
String S3 = sc.next();
int len1 = S1.length();
int len2 = S2.length();
int len3 = S3.length();
int[][][] dp = new int[len1 + 1][len2 + 1][len3 + 1];
int maxLength = 0;
int endIndex = -1;
for (int i = 1; i <= len1; i++) {
for (int j = 1; j <= len2; j++) {
for (int k = 1; k <= len3; k++) {
if (S1.charAt(i - 1) == S2.charAt(j - 1) && S1.charAt(i - 1) == S3.charAt(k - 1)) {
dp[i][j][k] = dp[i - 1][j - 1][k - 1] + 1;
if (dp[i][j][k] > maxLength) {
maxLength = dp[i][j][k];
endIndex = i - 1;
}
} else {
dp[i][j][k] = 0;
}
}
}
}
if (maxLength == 0) {
System.out.println(-1);
} else {
System.out.println(S1.substring(endIndex - maxLength + 1, endIndex + 1));
}
}
}